Explain the relationship between pressure,volume,and density of gases.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) Boyle's Law states that at constant temperature,the pressure $(p)$ of a fixed amount of gas is inversely proportional to its volume $(V)$.
Mathematically: $p \propto \frac{1}{V}$ (at constant $T$ and $n$)
$p = k_1 \frac{1}{V} \implies pV = k_1$
Since density $(d)$ is defined as mass $(m)$ divided by volume $(V)$,we have $d = \frac{m}{V}$,which means $V = \frac{m}{d}$.
Substituting this into Boyle's law $(pV = k_1)$:
$p \left( \frac{m}{d} \right) = k_1$
$p = \left( \frac{k_1}{m} \right) d$
Since $k_1$ and $m$ are constants for a fixed amount of gas at a constant temperature,we can write $\frac{k_1}{m} = k'$ (another constant).
Therefore,$p = k' d$,which means $p \propto d$.
This shows that at a constant temperature,the pressure of a fixed amount of gas is directly proportional to its density.

Explore More

Similar Questions

Which of the following statements is false?

$A$ gas occupies $600 \ mL$ at $27 \ ^\circ C$ and $730 \ mm$ pressure. What will be its volume at $STP$ in $litres$?

At $300 \ K$,a sample of $3.0 \ g$ of gas $A$ occupies the same volume as $0.2 \ g$ of hydrogen $(H_2)$ at $200 \ K$ at the same pressure. The molar mass of gas $A$ is $...... \ g \ mol^{-1}$ (nearest integer). Assume that the gases behave as ideal gases.

Find the number of moles of $CO_2$ present in a sample occupying $4 \times 10^{-3} \text{ m}^3$ at $1.104 \times 10^5 \text{ Nm}^{-2}$ pressure. Given: $R \times T = 2208 \text{ J mol}^{-1}$. (in $\text{ mole}$)

$A$ certain mass of a gas occupies a volume of $2 \,L$ at $STP$. To what temperature must the gas be heated to double its volume, keeping the pressure constant?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo